QUESTION 15 1.00000 During DNA synthesis, two phosphoanhydride bonds are broken

Question

QUESTION 15 1.00000 During DNA synthesis, two phosphoanhydride bonds are broken in deoxyribonucleotide triphosphates (Deoxyribose Base +3 phosphates) before the nucleotide (Deoxyribose + Base + 1 phosphate) is incorporated into the growing DNA strand. Why is this necessary? O The hydrolysis of the phosphoanhydride bonds has a very large -AG and is coupled with the incorporation of the nucleotides, which has a smaller, but positive, +AG. O Only DNA synthesis is an energetically unfavorable process, where as RNA synthesis is not. O Cells can only make deoxyribonucleotide triphosphates. They are incapable of making deoxyribonucleotide monophosphates (Deoxyribose + Base + 1 phosphate). O The phosphates that are cleaved off are used in the sugar-phosphate backbone of the growing DNA strand. QUESTION 16 1.00000 point Consider the Lineweaver-Burke equation shown below. If you incubated this system with 7 units of substrate, what initial rate would you expect? *Do not include units with your answer- Round your answer to the nearest 100th place, or two decimal places (eg 1.25, 0.17, 1.80, etc.)** 0.5+0.1667

Explanation / Answer

15) During DNA synthesis, two phosphoanhydride bonds are broken in deoxyribonucleotide triphosphates before nucleotide is incorporated into growing DNA strand. The phosphates that are cleaved during this process is used to form sugar phosphate backbone of the growing DNA strand. (option 4).

16) 1/V = 0.5 (1/S) + 0.1667

= 0.5/7 + 0.1667

= 0.071 + 0.1667

= 0.238

V = 1/0.238

= 4.201

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