-- Given an impedance of 5ohms - 58 degree with a current of 4A - 50 degree, wha

Question

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Given an impedance of 5ohms - 58 degree with a current of 4A - 50 degree, what is the magnitude of the voltage? Given an impedance with a current of 4A 13 degree and a voltage of 24V 40 degree, what is the magnitude of the impedance? Given an impedance of 4ohms 50 degree with a voltage of 20V - 9 degree, what is the magnitude of the current? Given an impedance with a current of 3A 12 degree and a voltage of 69V 38 degree, what is the angle of the impedance? Given an impedance of 3ohms 85 degree with a voltage of 31V 45 degree, what is the phase of the current?

Explanation / Answer

8.
Magnitude of voltage=i*R
   =4*5
=20 v
9.
impedence=voltage/current
   =24/4
=6 ohm

10.
current=voltage/impedence
=10/4
=5 A

11.
V=I*R
angle of voltage=angle of current+angle of impedence
38=12+angle of impedence
angle of impedence=26 degree

12.
phaseof voltage=phase of current+phase of impedence
45=phase of current+85
phase of current= -40 degree

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