An object is located at the origin at time t=0. An elastic band connects the obj
ID: 2828958 • Letter: A
Question
An object is located at the origin at time t=0. An elastic band connects the object to the point Q=(2,0). The object starts moving according to the parametic equations:
x(t)=t, y(t)= Square root of t
where t is time in seconds and the units on the axes are meters. The dotted line below shows the elastic band at a typical time t:
(a) The instantaneous rate of change of the length of the elastic band at time t=0 is ?
(b) The instantaneous rate of change of the length of the elastic band is 0 m/sec at time ?
Please show work, that'd be much appreciated. Thanks!
Explanation / Answer
s= sqrt((x-2)^2+y^2) ; x= t, y= sqrt(t)
ds/dt= ds/dx * dx/dt + ds/dy* dy/dt ==> ds/dt= (x-2)/sqrt((x-2)^2+y^2) * dx/dt+y/sqrt((x-2)^2+y^2)*dy/dt
since x= t, y= sqrt(t)==> ds/dt= (t-2)/sqrt((t-2)^2+t)+ sqrt(t)/(t-2)/sqrt((t-2)^2+t)* 1/2sqrt(t)
==> ds/dt= (t-3/2)/(t-2)/sqrt((t-2)^2+t)
at t=0 ==> ds/dt= -3/4
if ds/dt= 0 ==> t= 3/2s
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