For this question, type all word answers (such as PI or INFINITY) in all capital
ID: 2829625 • Letter: F
Question
For this question, type all word answers (such as PI or INFINITY) in all capital letters, and write any fractions as decimal answers. Consider the series 4/ln(n)+n We know that the p-series 1/n is divergent (because p= 1 is not larger than 1), and we know that the p -series 1/n2 is convergent (because p=2>1). Use the Limit Comparison Test to (with these two p-series) to determine if is convergent or divergent. Using the Limit Comparison Test with Using the Limit Comparison Test with By the Limit Comparison Test and the results above, the seriesExplanation / Answer
lim (4n)/(n+ln(n)) = 4 so c=4 for the first question
lim (4n^2)/(n+ln(n)) = INFINITY , so c=INFINITY for the second question
Trivially divergent since c=4 for the test with 1/n by limit comparison test
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