Calculating how much fertilizer to add to an area: Desired rate in lbs nitrogen

Question

Calculating how much fertilizer to add to an area: Desired rate in lbs nitrogen (N)/1,000 sq.ft/% nutrient (as a decimal) = fertilizer needed per 1,00 sq.ft. Total fertilizer needed/1,000 sq.ft. times area in sq.ft = lbs fertilizer needed for the area For example, to fertilize a lawn area50 times 100 ft at a rate of 1 lb of nitrogen (N) per 1,000 sq.ft with a 18-3-18 fertilizer, the following calculation is required 1/0.18 = 5.5 lbs fertilizer product/1,000 sq.ft 5.5/1000 times 5,000 (area) = 27.5 lbs total fertilizer needed A bag of lawn fertilizer typically weights 50 lbs. How much fertilizer product is needed apply 1 lbs N/1,000 sq.ft to a soccer field area 80,000 sq.ft with a 10-2-8 organic fertilizer Answer in lbs How much fertilizer product needed to apply 1 lbs N/1,000 sq.ft to a soccer field area 80,000 sq.ft with a 22-3-11 synthetic fertilizer Answer in lbs

Explanation / Answer

1. N: P: K ratio of fertiliser=10:2:8

Since rate of fertiliser=1lb/1000 square feet

% of nutrient N(in decimal)=10/100=0.1

Desired rate of lbs nitrogen/1000 square feet

=1/0.1=10lbs fertiliser product/1000 sq feet

Field area=80,000 sq feet

Total fertiliser required for 80,000 sq feet area=fertiliser product/1000 square feet *Area

=10/1000*80,000

=800 lbs

2. N:P:K ratio of the fertiliser=22:3:1

% nutrient of Nitrogen ( decimals)=0.22

Required nitrogen(lbs)/1000 feet=1/0.22=4.54lbs fertiliser product/1000 sq feet

Field area=80,000 sq feet

Total fertiliser required=fertiliser product/1000 square feet * Area

4.54/1000*80,000

=363.2lbs

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