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Question
amazon-Google search x e Test D wwwwwebassign.net/web/Student/Assignment-Responses/submit?depar 9481338 Find the two x-intercepts of the function f and show that f (x) at some point between the two x intercepts. f(x) x 7x 18 (x, y) (smaller x-value) (x, y) (arger x-value) Find a value of x such that f 0. points Lancaic10 32016 Determine whether Rolle's Theorem can be applied to f on the closed interval ta, bl. (Select all that apply.) t-9, al Yes, Rolle's Theorem can be applied No, because f is not continuous on the closed interval [a, b). No, because f is not differentiable in the open interval (a, b) No, because f (a) a f (b). If Rolle's theorem can be applied, find all values of c in the open interval (a, b) such that f (c) o. (Enter your answers as a c The height of an obyect e seconds anter it is dropped a height of iso meters sca) -+.9ta 1ao. And the average velocity from is of the ebject during the first 2 seconds. E) use Mean value Theorem to verify that at some time during the first seconds of tail. the instantaneous velocity equExplanation / Answer
1)f(x)=x^2-7x-18
for xintercept y=0
x^2-7x-18=0
x=9,-2
for these values the y coordinate=0
smaller x value =-2
larger x value =9
f'(x)=2x-7
2x-7=0
x=7/2
q2)rolles theorem
f(x)=x^-81/x
if the rooles theorem is applied only when it is continuous and differentiable in the closed interval[-9,9] and open interval (9,9)
it is not continuous at x=0,therefore rolles theorem cant be applied
if the rolles theorem can be applied then the value of c is f'(x)=0
c=9i where i is a complex part
Q3 here height g(t)=-4.9t^2 +180
at 2 seconds height attained =160.4 m
average velocity =total distance/total time =19.6/2 =9.8 m/s
b)from the mean value theorem the instantaneous velocity =f(2)-f(0)/2
=9.8 m/s
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