Calculus Please let me know if you need more time. Thank you in advance. Part A

Question

Calculus

Please let me know if you need more time. Thank you in advance.

Part A

A certain statistics instructor for Math3030 wants to assess the number of jokes receiving laughs per lecture. A random sample of 100 jokes was selected to participate in the assessment (during the semester so far, imagine the control the instructor had). According to one optimistic assessment the mean number of student laughing per joking occasion is 3.2 with a standard deviation of 2.6. Construct a 95% confidence interval for the mean number students laughing during the dissemination of instructor

Explanation / Answer

A) mean number of student laughing per joking occasion = 3.2

standard deviation = 2.6; sample size n = 100

Std Error = stdev/sqrt(n) = 2.6/sqrt(100) = 0.26

alpha = 1

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