Highway Design A section of highway connecting two hillsides with grades of 6% a
ID: 2841170 • Letter: H
Question
Highway Design A section of highway connecting two hillsides with grades of 6% and 4% is to be built between two points that are separated ba a horizontal distance of 2000 feet. At the point where the two hill-sides come together, there is a 50-foot difference in elevation.
a) design a secation of highway connecting the hillsides modeled by the function
(undefined) (-1000 less than or equal to x less than or equal to 1000). At the points A and B, the slope of the model must match the grade of the hillside.
b) use a graphing utility to graph the model.
c) use a graphing utility to graph the derivative of the model.
d) determine the grade at the steepest part of the transitional sexation of the highway.
Explanation / Answer
I started by putting point A at the origin (0,0), then point B would be at (2000,50)
I realized I was going to work with very large numbers, so I "scaled" my graph back by a factor of 50:1
so point A was still (0,0) but point B became (40,1)
let f(x) = ax^3 + bx^2 + cx + d
at (0,0) this would give me d = 0
so f(x) = ax^3 + bx^2 + cx
I then subst. (40,1) into that to get
1 = 64000a + 1600b + 40c (equ#1)
also f'(x) = 3ax^2 + 2bx + c
we know at (0,0) slope = .04
so ....c=.04
we know at (40,1) slope = .06
so.. .06 = 4800a + 80b + c
but c=.04
4800a + 80b = .02 (equ#2)
I then put c=.04 into equ#1, and solved this with equ#2 to get
a=1/32000
b=-13/8000
c=1/25
then finally
f(x) = (1/32000)x^3 - (13/8000)x^2 + (1/25)x
I set the derivative of that equal to zero, there was no real solution, so there is no max/min to this function.
there is a point of inflection at x=17.3
which translates into 17.3*50 = 865 m horizontal from A
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