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f(x) = (5x + 4) 2 f(x) = (4x 2 + 1) 4 f(x) = (-5x + 7) 4 f (x) = ( 3 - 6 x ) 140

ID: 2844102 • Letter: F

Question


f(x) = (5x + 4)2

f(x) = (4x2 + 1)4

f(x) = (-5x + 7)4

f (x) = ( 3 - 6x)140

f (x) = f (x) = 1/2 f (x) = 10 f (x) = - 5x/ f (x) = - 5/ f (x) = 1/(5x2 - 9x + 3)4 f (x) = (10x - 9) (5 x2 - 9x + 3) 5 f (x) = -4 (10x - 9) (5 x2 - 9x + 3) 5 f (x) = -4/(5x2 - 9x + 3) 5 f (x) = -4 (10x - 9) (5x2 - 9x + 3) 3 f(x) = f (x) 10x - 1/3(5x2 - x)2/3 f (x) = 10x/(5 x2 - x) 2/3 f(x) = 1/3 (5 x2 - x) 2/3 f (x) = 10x - 1/3 (5 x2 - x) = 1/3 f (x) = 1/4 x2 + 4 f (x) = - 8x/4 x2 + 4 f (x) = - 8x/(4 x2 + 4) 2 f (x) = - 8x - 4/(4 x2 + 4) 2 f (x) = - 1/(4 x2 + 4) 2 f (x) = f (x) = 11 - 5x4/2 f (x) = 1/2 f (x) = -5 x4/ f (x) = 1/2 f (x) = 1 f (x) = 8/(8x - 6) 3/2 f (x) = - 4/(8x - 6) 3/2 f (x) = - 1/2 (8x - 6) 3/2 f (x) = - 4/(8x - 6) 1/2

Explanation / Answer

1.D

2.B

3.A

4.D

5.B

6.A

7.D

8.B

9.C

10.D