(a) Find symmetric equations for the line that passes through the point and is p
ID: 2845346 • Letter: #
Question
(a) Find symmetric equations for the line that passes through the point
and is parallel to the vector
(b) Find the points in which the required line in part (a) intersects the coordinate planes.
point of intersection with xy-plane
point of intersection with yz-plane
point of intersection with xz-plane
Explanation / Answer
a) symmetric equations through (2, -5, 9) and parallel to vector <-1, 4, -3>
From part a, you get the symmetric equations for the line:
(x - 2) / (-1) = (y + 5) / 4 = (z - 9) / (-3)
You can also write parametric equations for the line:
x = x0 + at
y = y0 + bt
z = z0 + ct
x = 2 - t
y = -5 + 4t
z = 9 - 3t
b) intersection with xy plane means z = 0:
z = 0 gives 9 - 3t = 0 or t = 3
Then x = 2 - 3 = -1
y = -5 + 4(3) = 7
(-1, 7, 0)
intersection with yz plane means x = 0:
x = 0 gives 2 - t = 0 or t = 2
y = -5 + 4(2) = 3
z = 9 - 3(2) = 3
(0, 3, 3)
intersection with xz plane means y = 0:
y = 0 gives -5 + 4t = 0 or t = 5/4
x = 2 - 5/4 = 3/4
z = 9 - 3(5/4) = 21/4
(3/4, 0, 21/4)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.