please help me solve An object thrown vertically upward from the surface of a ce

Question

please help me solve

An object thrown vertically upward from the surface of a celestial body at a velocity of 24 m/s reaches a height of s = -0.6t2 + 24t meters in t seconds. Determine the velocity ? of the object after t seconds. When does the object reach its highest point? What is the height of the object at the highest point? When does the object strike the ground? With what velocity does the object strike the ground? An object is dropped from a tower, 256 ft above the ground. The object's height above ground t seconds after the fall is s(t) = 256 - 16t2. Determine the velocity and acceleration of the object the moment it reaches the ground.

Explanation / Answer

(a)

v(t) = 24-1.2t

(b)

highest point when v=0

=>

24-1.2t =0

=>

t = 20s

(c)

s(20) = -0.6*20^2+24*20 = -240+480 = 240

(d)

object strike the ground at t =40

(e)

the velocity when it hits ground = 24

2.

v(t) = -32t, a =-32

time when reaches ground:

0 =256-16t^2

=>

t =4

=>

v(4) = -128ft/s

a(4) = -32 ft/s^2

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