Prof Amaach and Climate Change Spring 2016 Assignment GREENHOUSE GASES AND CLIMA
ID: 284616 • Letter: P
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Prof Amaach and Climate Change Spring 2016 Assignment GREENHOUSE GASES AND CLIMATE CHANGE Earth Atmosphere is relatively thin shell. Half the mass of the atmosphere is within 5 Km (3.1 miles) of the surface, and 90 percent is within (12.4 miles). Twenty km is not very far about a 10-minutes drive on most interstate highways. By comparison Earth's radius is 6,378 km (3963 miles). Question 1: What percent of the Earth's radius is 20 kilometers? Answer: The major gases that comprise the Earth's atmosphere are shown in Table below. The properties of the gases (ignoring water vapor, which is variable in the atmosphere remain virtually constant to a high of about 25km Volume Molecular Weight T Weight Gas approximate) 75.00 78.000 Nitrogen 23.00 32 21.000 oxyg 1.3 00.930 400 on 0.05 Carbon dioxide 00.035 100.00 Average Atmosphere 100.000 29 Percentages do not add up to 100 due to rounding approximation, and ignoring water vapor and all minor and trace gases. .Weight is found by multiplying the volume by the molecular weight of that gas and dividing by the average molecular weight of the atmosphere. "Weighting the Atmosphere At sea level, the weight of 1 cm? of air is approximately 1 kilogram. This value, 1kg/ cm is also known as the atmospheric pressure. For this analysis, we will assume a featureless Earth without continents. This will simplify but not significantly alters your calculations. Question 2: How much does the atmosphere weigh over each square meter of surface Express this in tonnes (units of 1000 kg). Recall the conversion factors: 10 cm 1m 1 tonne- 1000 kg 10% g.Explanation / Answer
Question 1
Answer: 0.313 percent
We have radius of earth 6378 km
Then we have to de 20/6378=0.31357792
We have to convert in percentage by multiplying 100, 0.313*100 = 0.313 percent
0.313 percent of the earth radius is 20 kilometrs.
Earth crust generally very thin compare to earth radius.
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