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ID: 2847872 • Letter: #
Question
%3Cdiv%20class%3D%22c3%22%3E%3Cimg%20src%3D%0A%22https%3A%2F%2Fwebwork.math.nau.edu%2Fwebwork2_files%2Ftmp%2Fequations%2F80%2F4869fe4cfe6a0cb3a9612897451e451.png%22%0Aclass%3D%22c1%22%20alt%3D%22a_%7Bn%7D%20%3D%20%5Cdfrac%7Bn%5Ccos(n%5Cpi)%7D%7B2n-1%7D.%22%20%2F%3E%3Cbr%20%2F%3E%3C%2Fdiv%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3Efind%20%3Cimg%20src%3D%0A%22https%3A%2F%2Fwebwork.math.nau.edu%2Fwebwork2_files%2Ftmp%2Fequations%2F45%2F2de2f5cb9d1d79cf367d09c0a4f4c61.png%22%0Aclass%3D%22c1%22%20alt%3D%22%5Clim_%7Bn%5Crightarrow%5Cinfty%7Da_%7Bn%7D%22%20%2F%3E.%20If%20the%20sequence%0Adiverges%2C%20enter%20%22divergent%22%20in%20the%20answer%20box%20for%20its%20limit%3C%2Fp%3E%0A%3Cp%3E%3Cimg%20src%3D%0A%22https%3A%2F%2Fwebwork.math.nau.edu%2Fwebwork2_files%2Ftmp%2Fequations%2F33%2Fc0f53e11e5423b4eb7e89cc368f28d1.png%22%0Aclass%3D%22c2%22%20alt%3D%0A%22%5Clim_%7Bn%5Crightarrow%5Cinfty%7Da_%7Bn%7D%20%3D%22%20%2F%3E%3F%3F%3F%3F%3F%3F%3F%3F%3F%3F%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0AExplanation / Answer
as n-> infinity , Cos(n pi) diverges to 1, hence limit value
= lim n->infinity Cos(n pi) / 2 -(1/n) = 1/2
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