Question
please help
Use Newton's method to estimate the solutions of the equation 4x2 + x - 1 = 0. Start with x0 = - 1 for the left solution and x0 = 1 for the right solution. Find x2 in each case. Use Newton's method to estimate the one real solution of x3 + 2x - 3 = 0. Start with x0 = 0 and then find x2. x2 = (Round to four decimal places as needed.) Use Newton's method to obtain the third approximation x2, of the positive fourth root of 8 by calculating the third approximation of the right 0 of f(x) = x4 - 8. Start with x0 = 1. The third approximation of the fourth root of 8 determined by calculating the third approximation of the right 0 of f(x) = x4 - 8, starting with x0 = 1, is . (Round to four decimal places.)
Explanation / Answer
Question 1
For x0 = 1; x2= 0.390388
For x0 = -1; x2= -0.640388
Question 2
For x0 = 0; x2= 1.000032
Question 3
For x0 = 1; x2= 1.68179
