Find the absolute maximum and minimum of the function f(x,y) = x^2-y^2 subject t
ID: 2850584 • Letter: F
Question
Find the absolute maximum and minimum of the function f(x,y) = x^2-y^2 subject to the constraint x^2 +y^2=64. As usual, ignore unneeded answer blanks, and list points in lexicographic order. Absolute minimum value: Attained at( ,_)and(?-??-?)? Absolute maximum value: attained at ( ?) and (_____,............). Answer (s) submitted: Find the absolute maximum and minimum of the function f(x,y) = x^2 +y^2 subject to the constraint x^4+y^4 = 16. As usual ignore unneeded answer blanks, and list points in lexicographic order. Absolute minimum value: ______ attained at Absolute maximum value: attained at Answer(s) submitted:Explanation / Answer
1) f(x,y) = x2 - y2 ; x2 +y2 = 64
==> g(x,y) = x2 +y2 -64
using lagrange multipliers
f(x,y) = g(x,y)
==> <fx ,fy> = <gx ,gy>
==> <2x , -2y> = <2x ,2y>
==> 2x = (2x) ; -2y = 2y
==> 2x(1 - ) = 0 ; 2y( +1) = 0
==> x = 0 , y = 0
x = 0 ==> (0)2 +y2 = 64
==> y = +8 , -8
y = 0 ==> x2 + 02 = 64
==> x = +8 , -8
Hence critical points are (0 ,8),(0,-8),(8,0),(-8,0)
f(0,8) = 02 - 82 = -64
f(0, -8) = 02 - (-8)2 = -64
f(8,0) = 82 - 02 = 64
f(-8,0) = (-8)2 - 02 = 64
Hence minimum at (0,8) & (0,-8) and value of function = -64
maximum at (8,0) & (-8,0) and value of function = 64
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