I already have 1 and 2, just need 3 and 4. Thank you. Lim s rightarrow infinity
ID: 2852216 • Letter: I
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I already have 1 and 2, just need 3 and 4. Thank you.
Lim s rightarrow infinity F(s) = 0 A non-technical explanation for that is simple. According to the definition, F(s) = infinity integrate 0 e^-st f(t)dt. As s goes to infinity, the factor e^-st in the integral goes to zero very fast, which causes the whole integral to go to zero Knowing this gives us a way of determining that certain functions of s cannot be Laplace transforms of reasonable functions: if lim s rightarrow infinity F(s) 0 or if that limit does not exist, we know that F(s) cannot be the Laplace transform of a reasonable function f (t). Explain why F(s) = arctan s cannot occur as a Laplace transform of a reasonable function f (t). There is exactly one constant C for which F(s) = arctan s + C satisfies lim s rightarrow infinity F(s) = 0. Find this constant. No explanation is necessary. Then find the inverse Laplace transform of F(s) = arctan s + C for this constant. use the formula L {(-t)f(t)} = F'(s). Is the unit impulse aka Dirac Delta function (t) a reasonable function or not? Explain by using what we learned about its Laplace transform. Combine what you learned in the previous two parts to find an unreasonable function whose Laplace transform is arctan s.Explanation / Answer
I already have 1 and 2, just need 3 and 4. Thank you. Lim s rightarrow infinity
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