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The graph in Figure below models the spread of the Ebola Virus during an outbrea

ID: 2853933 • Letter: T

Question

The graph in Figure below models the spread of the Ebola Virus during an outbreak in Zaire.
Discuss the disease’s rate of increase changes over time. At what time is the rate of increase the
highest? Explain.

48. The graph in Figure below models the spread of the Ebola Virus during an outbreak in Zaire. Discuss the disease's rate of increase changes over time. At what time is the rate of increase the highest? Explain. ph in Hioure below moad wattim t 48) Figure: Number of Deaths Caused by Ebola Virus during Zaire Outbreak Number of Deaths) 300 y D(t) 240 180 120 t 60 4 8 10 t (measured in weeks) Source: Center for Disease Control and Prevention (A) t = 1 week (B) t = 4 weeks (C) t = 5 weeks (D) t = 10 weeks (E) none of the above

Explanation / Answer

The given graph gives the number of deaths as a function of time.

The derivative would be the rate of change of the number of deaths.

Now, basically, looking at the beginning part, the number of deaths increases over the same time intervals. So, upto a point, approximately t = 5, the rate of increase keeps increasing.

And then, at t = 5, the graph gradually starts tapering again, which means that after t = 5, the rate of change of the number of deaths slowly decreases.

In a real life scenario, this can be thought this way : There were a few ebola related deaths in the beginning. But then the number of deaths started increasing and people realized thatt it could very well be ab outbreak. The rate of increase reached maximum at t = 5 approx. At this sttage, some kinda drastic containment was done and vaccination provided because of which the rate of increase od deaths sarted decreasing again...

Now, when did the rate of increase become highest?
This happened at t = 5 because it is at t = 5 when the concavity of the graph changes fron concave down to concave up....

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