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a) The rate of thermal expansion for 33 permil seawater is 0.00019/C . hints: Us

ID: 285522 • Letter: A

Question

a) The rate of thermal expansion for 33 permil seawater is 0.00019/C . hints: Use this factor and the volume of the cuboid (problem 3) to determine the added volume caused by a 1C ocean warming in cubic meters, volume * 0.00019/C * 1 C. (Use scientific notation and keep 3 significant figures, eg. 1.00E10); Volume of cuboid = 1.335E18 m^3

b) Suppose the cuboid’s sides (surface area) cannot change, only the depth. How much must the cuboid’s water level rise to accommodate the new volume? hints: This is the approximately the sea level rise caused by a 1 C warming of the ocean in meters, depth * 0.00019/C * 1C. (Keep 1 decimal places, eg. 1.0); Depth = 3688 m

Explanation / Answer

a)  The rate of thermal expansion for 33 permil seawater is 0.00019/C,

Volume of cuboid = 1.335E18 m3

Therefore, the added volume caused by a 1oC ocean warming is = volume * 0.00019/C * 1 C = 1.335E18 * 0.00019 = 2.54E14m3

b) Similarly, if the thermal expansion only changes depth at a rate of 0.00019/C,

depth = 3688 m

Therefore, the added depth or the rise in water level caused by a 1oC ocean warming is = depth * 0.00019/C * 1 C = 3688 * 0.00019 = 0.7 m