Entered Result 1/(x+6) correct 1/(x-6) correct In(x+6) In(x6) correct In(x-6) In
ID: 2855726 • Letter: E
Question
Entered Result 1/(x+6) correct 1/(x-6) correct In(x+6) In(x6) correct In(x-6) In(x - 6) 1/w correct In(w) The domain of your function doesn't match that of the correct answer In(w) in(xn2)-36 In(23 The domain of your function doesn't match that of the correct answer At least one of the answers above is NOT correct. (1 point) Calculate the integral below by partial fractions and by using the indicated substitution. Be sure that you can show how the results you obtain are the same. 2r dr First, rewrite this with partial fractions: dz= z-36 In(x+6) +In(x-6) +C Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution to 2-36 to find the integral: +C = z7-36 In(xA2-36) For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer)Explanation / Answer
The first three red boxes need a modulus operation
integral of 1/x is ln |x|
where |x| represent abs(x)
hecne the answers should be :
ln |x-6|
ln |w|
and ln |x^2 - 6|
Similarly for the answer to the integration : It should always be ln ( |argument |)
The answer will be :
x ln |x^2 - 1| - 2x -ln |1-x| + ln|x+1| + C
Please split the last question.
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