In the mosquito Anopheles culicifacies, golden body (go) is a recessive X-linked

Question

In the mosquito Anopheles culicifacies, golden body (go) is a recessive X-linked mutation, and brown eyes (bw) is a recessive autosomal mutation. A homozygous XX female with golden body is mated to a homozygous XY male with brown eyes. Predict the phenotypes of their offspring. If the progeny are intercrossed, what kinds of progeny will appear in the F2 and in what proportions?

Explanation / Answer

The cross is go/go +/+ female ´ +/Y bw/bw male --> F1: go/+ bw/+ females (wild-type eyes and body) and go/Y bw/+ males (golden body, wild-type eyes). An intercross of the F1 offspring yields the following F2 phenotypes in both sexes. Body Eyes Genotype Proportion golden brown go/go or Y bw/bw (1/2) ´ (1/4) = 1/8 golden wild-type go/go or Y +/bw or + (1/2) ´ (3/4) = 3/8 wild-type brown +/go or Y bw/bw (1/2) ´ (1/4) = 1/8 wild-type wild-type +/go or Y +/bw or + (1/2) ´ (3/4) = 3/8

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