A force of 10 pounds is required to stretch a spring from its natural length of

Question

A force of 10 pounds is required to stretch a spring from its natural length of 8 inches to a length of 10 inches. How much work is done in stretching the spring from its natural length of 14 inches? A water tank has the shape of the surface generated by revolving the parabola segment y = x^2, 0 x 2 about the y-axis. If the tank is filled to a depth of 3 feet with a fluid weighing 80 lbs. per cubic foot, find the work W required to pump the contents of the tank to a height of 2 feet above the top of the tank.

Explanation / Answer

4. You either have to use inches or feet, which requires a conversion.
It should not be a big problem, however, since 10 inch=5/6 ft and
14 inch=7/6 ft

determine the spring constant k...
F = kx
10 lbs = k*(5/ 6ft)
12lbs/ft= k

W = (1/2)*k*x^2
W = (1/2)*(12lbs/ft)*(7/6 ft)^2
W = 49/6ft-lbs .(answer)

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