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Pretend down syndrome is a recessive trait and is represented by ss. 80% of affe

ID: 28604 • Letter: P

Question

Pretend down syndrome is a recessive trait and is represented by ss. 80% of affected ss people cannot have children. However, As and AA people are not affected. (AA being homozygous dominant for no trait, As being Heterozygous for trait)

Based off of 10,000 people,

AA = 7561

As = 2416

ss = 23 (With down syndrome)

a) What are the genotype, allele, and the phenotype frequencies?

b) Is this population in HWE (Hardy-Weinberg Equilibrium?) Please include work and reason why, I actually need to learn this for my test coming up.

Also, please use the chi-square distribution

Explanation / Answer

Pretend down syndrome is a recessive trait and is represented by ss. 80% of affected ss people cannot have children. However, As and AA people are not affected. (AA being homozygous dominant for no trait, As being Heterozygous for trait)

Based off of 10,000 people,

AA = 7561

As = 2416

ss = 23 (With down syndrome)

a) What are the genotype, allele, and the phenotype frequencies?

b) Is this population in HWE (Hardy-Weinberg Equilibrium?) Please include work and reason why, I actually need to learn this for my test coming up.

Also, please use

P^2+2pq+q^2=1

q^2=23/10000

q= square root of 0.0023=0.047

p+q=1

p=1-0.047=0.953

genotype

Observed

Expected

O-E

(O-E)^2/E

AA

P^2

7561

0.953 x0.953 x10000=9082

305

As

2pq

2416

2x0.953x 0.047 x10000=896

ss

23

0.047 x0.047x10000=2209

q^2

10000

CHISQUARE =(O-E)^2/E

CALCUALTED VALUE IS MORE THAN TABLE VALUE

HENCE THE POPULAYION IS NOT IN HARDY WEIBNERG EQUILIBRIUM

genotype

Observed

Expected

O-E

(O-E)^2/E

AA

P^2

7561

0.953 x0.953 x10000=9082

305

As

2pq

2416

2x0.953x 0.047 x10000=896

ss

23

0.047 x0.047x10000=2209

q^2

10000

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