I need help with figuring out the range. can you please help? And show me the st

Question

I need help with figuring out the range. can you please help? And show me the steps.

"A Chapter 10: Section 10.2 e Chegg Study | Guided So × -> C fi Dwww.webassign.net/web/Student/Assignment-Responses/submit?dep-13713864#013 Consider a projectile launched at a height h feet above the ground and at an angle with the horizontal. If the initial velocity is v0 feet per second, the path of the projectile is modeled by the parametric equations x t vo cos and y = h (vo sin )t-16t2. A rectangular equation for the path of this projectile is y = 8 + x-0·006x2 (a) Eliminating the parameter t from the position function for the motion of a projectile to shows that the rectangular equation is as follows -16 (sec( 16 (sec(e)-x2+tan()x + h (b) Find h, vo, and ' (Round your answers to two decimal places.) V0 = 73.02 = 1.79 (c) Use a graphing utility to graph the rectangular equation for the path of the projectile. Confirm your answer in part (b) by sketching the curve represented by the parametric equations 70 60 50 40 30 20 50 100 150 200 50 100 150 200 70 60 50 40 30 20 70 60 50 40 30 20 50 100 150 200 20 40 60 80 100 (d) Use a graphing utility to approximate the maximum height of the projectile. (Round your answers to two decimal places.) 50 ft What is the approximate range of the projectile? 164.9 ft 6/24/2016

Explanation / Answer

The approximate range of the projectile is x co-ordinate on the graph where graph of the projectile cuts the x axis.

That is where the y co-ordinate =0.

Using graphing utility it comes as x = 174.3

or we can find out root for y = 8+x - 0.006x^2

one root is negative ( so rejected) and the other is x = 174.3

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