Do Problem 12 (b) . This is a normal distribution problem . You can either use t

Question

Do Problem 12 (b). This is a normal distribution problem. You can either use the wolframalpha or the on-line calculatorintroduced in the Section 6.6 Learning Guidance to do the calculation (Be careful to use the correct input format). Pay attention, 6 feet = 72 inches.

Show your result in the decimal form (not the percentage form) with three digits on the right side of decimal point.

I know (a) is 0.84 but i'm haveing trouble figuring out the answer to (b)

12. Human heights According to the National Health Survey, the heights of adult males in the United States are normally distributed with mean 69.0 inches and standard deviation 2.8 inches. (a) What is the probability that an adult male chosen at random is between 65 inches and 73 inches tall? (b) What percentage of the adult male population is more than 6 feet tall?

Explanation / Answer

Part b)

Mean = 69 inches

SD = 2.8 inches

b) 6 feet ---> 72 inches

Lets find z for when x = 72

z = (x - mean) / SD

z = (72 - 69) / 2.8

z = 1.0714285714285714

Now, we need to find P such that z > 1.0714285714285714 (as it says more than 6 feet tall)

This is the link i am using ----> https://www.easycalculation.com/statistics/p-value-for-z-score.php

Enter z = 1.0714285714285714

And since we are looking for more than 6 feet tall, we are checking for the right tailed value, which is 0.1420 = 14.2% here

So, answer ----> P(x > 6 feet) = 14.2% ----> ANSWER

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