what is the hydraulic head at the surface of a lake (elevation 1262 ft above sea

Question

what is the hydraulic head at the surface of a lake (elevation 1262 ft above sea level) that is 200 feet deep? what is the hydraulic head 100 feet below the surface of the lake? explain your answers. what is the hydraulic head at the surface of a lake (elevation 1262 ft above sea level) that is 200 feet deep? what is the hydraulic head 100 feet below the surface of the lake? explain your answers. what is the hydraulic head at the surface of a lake (elevation 1262 ft above sea level) that is 200 feet deep? what is the hydraulic head 100 feet below the surface of the lake? explain your answers.

Explanation / Answer

Hydraulic head of a surface water feature is the surface water elevation measured above sea level in unit length.

The total hydraulic head (h) is the sum of elevation head (z) and the pressure head (p).

for a surface water feature,

h = z + p, where p = 0

Therefore, h = z

So the hydraulic head at the surface of a lake (elevation 1262 ft above sea level) is 1264 ft.

100 ft below the surface of the lake, with a depth of 200 ft, the hydraulic head would be,

h = z (1264 - 200) + p (100)

h = 1164 ft.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.