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Chrome File Edit View History Bookmarks People Window Help O 4) A 73% D Sun Oct 16 16:19 a EE Math 192. Homework section x Search Results x C Calculus question I Chegg CO x yutaka Ce www.webassign.net/web/Student/Assignment-Responses/submit?dep 14263649#Q6 P MyLab & Mastering... Craigslist The Dare TV Apple Apps Desire2L. Home ite WebAssig Rate My Professors. autos Diablo Valley Colle SparkNotes Mobile. 10. O -8 points scalcET8 3.8.021 My Notes Ask Your Teacher (a) If $3000 is invested at 4% interest, find the value of the investment at the end of 9 years if the interest is compounded as follows. (Round your answers to the nearest cent.) (i) annually (ii) semiannually (iii) monthly (iv) weekly (v) daily (vi) continuously (b) If A(t) is the amount of the investment at time t for the case of continuous compounding, write a differential equation satisfied by A(t). dA dt Find the initial condition satisfied by A(t). A(0) Need Help? LRead it Talk to a Tutor 11. O -4 points scalcET8 3.8.504 XP. My Notes Ask Your Teacher Bismuth-210 has a half-life of 5.0 daysExplanation / Answer
P= 3000$
r = 4%
t = 9years
1) anually
CI = P( 1+ r/ 100 ) ^n
= 3000 ( 1+ 4/100)^9
= 3000 ( 1 + 1/25)^9
= 3000 ( 26/25)^9
= 3000 * 1.42 = 4269$
2) semianually
P=3000
r = 2%
t = 18
CI = P( 1+ r/ 100 ) ^n
= 3000 ( 1+ 2/100)^18
= 3000 ( 1 + 1/50)^9
= 3000 ( 51/50)^9
= 3585.3$
3. monthly
P = 3000
r = 4/12 = 1/3 %
t = 9*12 = 108
CI = P( 1+ r/ 100 ) ^n
= 3000 ( 1+ 1/300)^108
= 3000 ( 1 + 1/300)^108
= 3000 ( 300/301)108
= 4297.4$
4. weekly
P = 3000
r = 4/48 = 1/12
t = 9*48 = 432
CI = P( 1+ r/ 100 ) ^n
= 3000 ( 1+ /12*100)^432
= 3000 ( 1 + 1/1200)^432
= 3000 ( 1201/1200)^432
= 4299.3$
v) daily
P= 3000
r = 4/ 365
t = 9*365 = 3285
CI = P( 1+ r/ 100 ) ^n
= 3000 ( 1+ 4/365*100)^3285
= 3000 ( 1 + 1/9125)^3285
= 3000 ( 9126/9125)^3285
= 4299.90$
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