(a) You will note on the map that the glacier\'s terminus does not follow a stra
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Question
(a) You will note on the map that the glacier's terminus does not follow a straight line but flows around the c the landscape. But, to obtain an estimate, you decide to base your estimate along a straight-line (the red, dashed that intersects the glacial termini for different years) ontou rs of line Measure the amount of retreat from 1843 to 1999 along the dashed line. It is lobO m mine the average rate of the retreat during that period ( hbo m/156 years aem/yr) note that the rate has not always been consistent. In some time periods it appears to retreat more quickly than others. You decide to compute the rates during different shorter time periods. . Determine the rate of retreat along the dashed line from 1906 to 1999. I s8m/yr 0,7- 6 Determine the rate of retreat along the dashed line from 1843 to 1906, 344 m/yr .. (b) You have computed three rates of retreat over three different time periods. The following picture shows a recent view of this glacier. It is now approximately 6.2 km from its terminus to its top, or head. First, (a). Divide 6.2 km by each rate (remember to be careful to use the same units) to give you three different time periods. These are , determine estimates for the potential life of this glacier using the three rates you determined in part years years 3 years 2010 terminus Head of Athabasca Glacier 1938 terminusExplanation / Answer
In 1938 the lenght of terminus is 5.8cm =1660m
In 2010 the lengh of terminus is 5.5 cm= 1574m
The head of athabasca glacier is0.9 cm=231.82m
(a) The average rate of retreat during the period 1843 to 1999 (1660m/156y)=10.64m/y
The rate of retreat along the dashed line from 1906 to 1999 (1574m/93y)=16.92m/y
The rate of retreat along the dashed line from 1843 to 1906 (231.82m/63y)=3.6796m/y
(b) dividing by 6.2km each rate 6.2km=6200m
(1)6200/10.64= 582.706 years
(2) 6200/16.92= 366.43 years
(3) 6200/3.6796= 1684.96 years
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