A light block hangs at ret from the end of a spring when it is pulled down 10 cm

Question

A light block hangs at ret from the end of a spring when it is pulled down 10 cm and released. Assume the block oscillates with an amplitudes of 10 cm on either side of its initial position, and with a period of B s. Find a function phi(t) that gives the displacement of the block t seconds after it is released, where d(t) > 0 represents downward displacement. d(t) = cos () (Simplify your answers. Type exact answers. Using pi as needed. Use angle measures greater than or equal to 0 and less than 2s.)

Explanation / Answer

Maximum amplitude = 10 cm

Hence the period = 8 seconds

2pi * t = 8

t = pi/4

Therefore the function will be of the form d(t) = 10sin(pi/4*t) = 10cos(pi/4*t + pi/2)

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