20) the percentage of people, P, below the poverty level in the US is given in t

Question

20) the percentage of people, P, below the poverty level in the US is given in table 1.6

a) find a formula for the percentage in poverty as a linear function of time in years since 2000

b)use the formula to predict the percentage in poverty in 2006

c) what is the differece between the prediction and the actual percentage, 12.3%?

year since 2000 0 1 2 3

p(percentage) 11.3 11.7 12.1 12.5

38) a car starts slowly and then speeds up. eventually the car slows down and stops. graph the distance that the car has traveled against time.

48) on black monday october 28 1929 the stock market on wall street crashed. the dow jones average dropped from 298.94 to 260.64 in one day. what was the relative change in the index?

38) a) true or flase: the annual us consumption of biodiesel gre exponentially from 2003 to 2005. justify your answer without doing any calculations

b) according to this data, during what single years(s), if any, did the us consumption of biodiesel at least double?

c) according to this data, during what single years (s), if any, did the us consumption of biodiesel at least triple?

year 2003 2004 2005 2006 2007 2008 2009

% growth -12.5 92.9 237 186.6 37.2 -11.7 7.3

6) 100=25(1.5)^t => natural logarithms

24) P=7e^pi t => growth and decay

32) a) what is the annual percent decay rate for p=25(0.88)^t, with time, t, in years?

b) write this function in the form P=P0ekt what is the continuous percent decay rate?

14) Use the variable "U" for the inside function to express each of the following as a composite function:

a) y=(5t^2-2)6

b)P=12e-0.6t

c)C=12ln(q3 +1)

Explanation / Answer

calculus answers

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32) a) what is the annual percent decay rate for p=25(0.88)^t, with time, t, in years?

p = 25(1-.12)^t

so annual decay rate is 12%

32(b) continous percent decay rate

A=A0ert

.88 = 1 ert

t=1

.88= er

ln (.88) =-r

r=0.127

continous percent decay rate is 12.7%

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14. composite function

a) y=(5t2-2)6

let5t2-2 =u

y=u6

b)P=12e-0.6t

u=0.6t

p=12eu

c)C=12ln(q3 +1)

u=q3 +1

C=12lnu

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