If a ball us thrown vertically upward with velocity of 50ft/s, then it\'s height

Question

If a ball us thrown vertically upward with velocity of 50ft/s, then it's height after t seconds is h (t)= 50t-5t^2

A. What is the maxed height reached by the ball?

B. What is the velocity of the ball when it is 120 ft above the ground on its wa7 u0? on its way down?

(V) If a ball ia thrown vertically upwund withi valbcity od 50 fy's, then its height sfer t veconds a) Whst is the maximum height reachod try the ball? b) whas tche veloorty of the ball when it is 120 n above the ground on its way up? Ot, its Whet is the velocity of the ball when it is 120 n ahowe the ground ca its way up? Oa ita What i wiy down

Explanation / Answer

(A) h(t) = 50t - 5t^2

h'(t) = 50 - 10t

50 - 10t = 0 means t = 5

h(5) = 50(5) - 5(5^2) = 125 ft

(B) When h = 120, 120 = 50t - 5t^2

Upon solving the above equation, we get t = {4, 6}

h'(4) = 50 - 10(4) = 10 ft/s (while going up)

h'(6) = 50 - 10(6) = -10 ft/s (while going down)

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.