Exercise Twenty Two/Location and Distance on Earth 35 90 N FIGURE 22.8 Globe and

Question

Exercise Twenty Two/Location and Distance on Earth 35 90 N FIGURE 22.8 Globe and string method for determining the distance between two places on Earth along a great circle other than the equator or a meridian. In the example llustrated, the distance between X and Y along the great circle is 30, which is approximately equivalent to 2070 miles (3330 kilometers). 45'N 30 N 75 N 60° 45 3 45'N .X 15 N 60.4530. 15* 0° Great circle 90 S A. Using a string, measure the 15 S distance between the points. 30 S 45 S B. Determine the distance in degrees between the points by laying the string along the equator 75 S measuring the marked string's length in degrees of longitude along the equator, which is also a great circle (FIGURE 22.88). Step 4: Multiply the number of degrees along the great circle by 69 miles or 111 kilometers to arrive at the approximate distance. IFor example, the great circle distance between X and Y in Figure 22.8 would be approximately 2070 miles (30" x 69 miles/degree), or 3330 kilometers (30 x 111 kilometers/degreelJ 1. Use the g meters from Memphis, Tennessee, to Tokyo, Japan. a. Degrees b. Distance along the great circle between Memphis and Tokyo: along the great circle between Memphis and Tokyo: m. km 2. Use the globe a home that has international service to London, England. Using the globe and string method, complete the following. a. b. Distance Degrees along the great circle between the airport and London, England nce along the great circle between the airport and London, England: mi km What wou speed of 550 miles per hour.) .hr 22.7 Determining Distance Along a Parallel except the equator are small circles, the length of 1 of longitude along a the Since all parallels

Explanation / Answer

1. a) The number of degrees on equatorial great circle is 129, i.e. from 0 to 129E.

b) The distance between Memphis and Tokyo using the string and globe method is therefore 8901 miles or 14319 km.

2. a) Number of degrees on equatorial great circle is 81, i.e. from 0 to 81E.

b) Based on the number of degrees, i.e. 81, the distance between the nearest airport (from my home) to London is 5589 miles or 8991 km.

c) Given that speed is 550 miles per hour. Distance is 5589 miles. So, approx flight time will be 5589 / 550 = 10 hours.

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