MATH 2321 -Calculus for Life Sciences-section 351 (sp18) mework ATH 2321- Calcul

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MATH 2321 -Calculus for Life Sciences-section 351 (sp18) mework ATH 2321- Calculus for Life Sciences-section 351 (sp18) Save omework: Section 6.2 Homework e Hw Score: 11.82%, 1.18. 70f 10 (2 complete) ? core: 0 of 1 pt Question Help * Bus Econ 6.2.25 A fence must be built to enclose a rectangular area of 5000 t2. Fencing material costs $3 per foot for the two sides facing north and south and $6 per foot for the other two sides. Find the cost of the least expensive fence. The cost of the least expensive fence is $ (Simplify your answer.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Answe

Explanation / Answer

Let the sides be x and y

x y = 5000

y = 5000/x

Cost = 3(2x) + 6 (2y) = 6x + 12 y

C = 6x + 12(5000/x) = 6x + (60000/x)

C ' = 6 -(60000/x2)

C ' =0

6-(60000/x2)=0

x2=10000

x = 100ft

y =5000/100 = 50 ft

Cost = 6x + 12 y = 6(100)+12(50) = $1200

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