The price-demand equation for hamburgers at a fast food restaurant is given by t

Question

The price-demand equation for hamburgers at a fast food restaurant is given by the following equation x+400p 2500 Currently the price of a hamburger is $4.00. If the price is increased by 10%, how will the revenue be affected? If the price is increased by 10%, the revenue will increase be equal to 0 remain the same decrease Match the conditions f(x)>0 and f">0 on (a.b) with one of the graphs (A) - (D) f(x) f(x) f(x) f(x) Graph correctly displays the conditions f'(x) 0 and f" 0 on (a.b) Type A, B, C, or D) 3 Find the relative rate of change of fx)- 120x 0.3x The relative rate of change of f(x) is

Explanation / Answer

1.x+400p=2500

so

x= 2500-400p

revenue.

R(p)= xp= (2500-400p)p= 2500p-400p2

Thus marginal revenue

R'(p)=2500-800p

at p =4 $

R'(p)= 2500-3200= -700

so marginal revenue is negative that means increase in price will decrease the revenue.

so

REVENUE WILL DECREASE .

2.

F'(x) >0 means function is increasing

F''(x)>0 means graph is concave upward.

so

answer =c

3.

f(x)=120x-0.3x2

relative rate of change =f'(x)= 120-0.6x

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