The height feet) of an ob ect mov ng vertically is given by s :-16t2 + 25 t + 19
ID: 2886682 • Letter: T
Question
The height feet) of an ob ect mov ng vertically is given by s :-16t2 + 25 t + 192, where t is n seconds. Find the oble rs velocity at t = 2 its man and its velocity when s -0 um height and when it occurs, The velocity of the object at t -2 seconds is t/second. (Simplify your answer. Type an integer or a decimal.) The maximum height occurs att-seconds. (Simplity your answer. Type an integer or a decimal.) The maximum height is feet. (Simplify your answer. Type an integer or a decimal.) The velocity when s 0 is feet/second Round to the nearest hundredth. Enter your answer in each of the answer boxes.Explanation / Answer
s= -16t2+256t +192
velocity, v(t) = s '(t) = -32 t + 256 ft/second
maximum height
s'(t) =0
-32 t + 256 =0
t = 8 sec
Maximum height occurs at t=8 sec
s(8) = -16(8)2+256(8) + 192 = 1216 ft
Maximum height is 1216 ft
When s =0,
16t2-256t -192 =0
t= 16.7 sec
v(16.7) = -32(16.7) + 256 = -278.4 ft/sec
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.