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Pad 8:00 PM webassign.net Need Help? Read ItWatch ItTalk to a Tutor 10. 2/6 points Previous Answers LarCalc11 2.5.057 My Notes Find equations for the tangent line and normal line to the circle at each given point. (The normal line at a point is perpendicular to the tangent line at the point.) Use a graphing utility to graph the equation, the tangent lines, and the normal lines. x2 + y2 = 25 At (3, -4) 10 -10 -8-64-2 10 10 10 10 10-8-6 -10 -8-6 10 Tangent line: y = Normal line: = At (-4, 3) 10 10Explanation / Answer
At (3, -4):
x² +y² =25
2x+2ydy/dx =0
dy/dx =-x/y
dy/dx = 3/4
Hence
tangent line : y=(3/4)x -(25/4)
Normal line : y=(-4/3)x
==============
At point (-4,3)
x² +y² =25
2x+2ydy/dx =0
dy/dx =-x/y
dy/dx = 4/3
Hence
tangent line : y=(4/3)x +(25/3)
Normal line : y=(-3/4)x
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