Original equation... y = -15.967x 2 + 10.746x + 0.0839 1. Determine how high the

Question

Original equation... y = -15.967x2 + 10.746x + 0.0839

1. Determine how high the ball is at exactly time t=0.4 seconds  h(0.4) = ____ feet.
2  Find an equation that would give the instantaneous velocity at any time t. (Be sure to use the entire equation when determining the answer to this problem. Coefficients should be listed to the thousandth.
3.Determine the velocity of the ball at time t = 0.2 seconds. v = ______ ft/sec
4 a. Determine when the velocity of the ball was 10 ft/s. h'(t)=10, when t = _____ seconds.
4 b.use the answer from the previous question to determine how high the ball went h=______feet

Explanation / Answer

y=-15.967x2+10.746x+0.0839

1. h(0.4)=1.82758 feet

y '= -15.967(2)x +10.746 =-31.934x+10.746

c . y '(0.2)= -31.934(0.2)+10.746=4.35d2 ft/sec

d.y'(t)=10

-31.934x+10.746=10

x=0.0234 sec

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