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i Safari File Edit View History Bookmarks Window Help 48% i Tue 8:46 PM edugen wileyplus.com WileyPLUS WileyPLUS Find A Solution To The Equation If Possible. Give Chegg.com WlleyPLUS: MyWlleyPLUS Help1 Contact Us | Log Out WileyPLUS Hughes-Halett, Calculus: Single Variable, Te CALCULUS (MTH 141/142) Home Read, Study & Practice Assignment Gradebook ORION Downloadable eTextbook Assignment Open Assignment NEXT ASSIGNMENT RESOURCES y = a(1.11)'.y = b(1.08)'.y-d104). Sec1.2 assuming a, band c are constants.Note that the function values have been rounded to two decimal places. Question 002 Chapter 1, Section12 2 1.08 2.223 3.78 3 1.12 22.46 4 4.08 1.17 32.745 4.41 5 1.22 4 3.046 4.76 6 1.27 5 3.3775.14 Question 007 Chapter 1, Section12 008 Question 010 Chapter 1, Sectiort 1.2, Enter the formulas with the correct values for the constants a, b, and c Question 015a Chapter 1, Sectiort 1.2, h(s) = Question 017cd Chapter 1, Section12 f(s) = a g (s) - All Rights Reserved. A Division of John Wilcy &Sans;, Ins Version 4.24.4.5

Explanation / Answer

Lets look at (2,1.08) and (3,1.12)

y = a*b^x

1.08 = a*(b^2)
1.12 = a*(b^3)

Dividing :
0.9642857142857143 = 1/b

0.9642857142857143 = 1/b

b = 1.0370370370370370217

With this, lets find a :
1.08 = a * 1.0370370370370370217^2
a = 1.004

So, we have
h(s) = 1.004 * (1.04)^s --> ANS

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For f(s) :
(1,2.22) and (2,2.46)

Again y = a*b^x

2.22 = a*b
2.46 = a*b^2

Dividin' :
1.1081081081081081 = b
b = approx 1.11

Now, solvin for a :
2.22 = a*1.1081081081081081
a = 2.003

So, we have
f(s) = 2.003 * (1.11^s) ---> ANS

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g(s) :
3,3.78 and 4,4.08

y = a*b^x gives us :

3.78 = a*b^3
4.08 = a*b^4

Dividin' :
1.0793650793650794 = b
b = 1.0793650793650794

Now, findin' a :
3.78 = a * 1.0793650793650794^3
a = 3.0059843145735800054, as in 3.006

So, we have
3.006 * (1.08^s) ----> ANS

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