00.05 points 1 Previous Answers LarCalc11 4.1.061 MI. My Notes Ask Your Ta Assum

Question

00.05 points 1 Previous Answers LarCalc11 4.1.061 MI. My Notes Ask Your Ta Assume the acceleration of the object is ate)--9.8 meters per second per second. (Neglet air resistance.) thrown upward (from a height of 2 meters) to reach a maximum height of 600 meters? (Round your answer to one decimal place.) X m/sec AnswerSave Practice Another Version 050 05 points 1 Previous Answers LarCalo11 4.1.063 On the moon, the acceleration of a free-falling o My Notes Ask Your Tea bject is -1.6 meters per second per second. A stone is drooped from dliff on hmonn

Explanation / Answer

600m is measured from ground level,

distance above launching point = 600 - 2 = 598 m

the formula is

v^2 = 2gh

plugging in,

v^2 = 2*9.8*598

v = sqrt(2*9.8*598)

v= sqrt(11720.8)

v= 108.26 m/sec

= 62.296 m/sec

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