9. O 0/1 points | Previous Answers Ic10 4.1.055 Use a(t) - -32 ft/sec2 as the ac
ID: 2891451 • Letter: 9
Question
9. O 0/1 points | Previous Answers Ic10 4.1.055 Use a(t) - -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.) verticlly with a velocity of 16 feet per second, releases a sandbag at the instant when the balooni 64 feet above the ground. (e) How many seconds after its release will he bag strike the ground? (Round your answer to two decimal places.) t= 2.00 X sec (b) At what velocity will t trike the ground? (Round your answer to three decimal places.) t/sec 10. ..1 points LaCalc10 4.1.056 Use a(t)- -9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.) A baseball is thrown upward from a height of 2 meters with an initial velocity of 9 meters per second. Determine its maximum helght. (Round your ans places.)Explanation / Answer
9)
a(t)=-32 , v(0)=16, s(0)=64
v(t) =v(0) +a(t) dt
v(t) =16 +-32 dt
v(t) =16 -32t
s(t)=s(0)+v(t) dt
s(t)=64 +(16-32t) dt
s(t)=64+16t -16t2
(a)
when bag strikes the grounnd , s(t)=0
=>64+16t -16t2=0
=>16(4+t -t2)=0
=>t2-t =4
=>t2-t+(1/4) =17/4
=>(t-(1/2))2=(17/4)
=>t-0.5=2.0615528
=>t=2.5615528
=>t=2.56sec
(b)
v(2.5615528) =16 -32(2.5615528)
=>v(2.5615528)=-65.970 ft/sec
hits the ground with v=-65.970 ft/sec
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10)
a(t)=-9.8 , v(0)=9, s(0)=2
v(t) =v(0) +a(t) dt
v(t) =9 +-9.8 dt
v(t) =9- 9.8t
s(t)=s(0)+v(t) dt
s(t)=2 +(9- 9.8t) dt
s(t)=2 +9t- 4.9t2
at maximum height ,v(t)=0
=>9- 9.8t=0
=>t=9/9.8
maximum height =s(9/9.8)
maximum height=2 +9(9/9.8)- 4.9(9/9.8)2
maximum height=6.133 m
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