F (x) = x + 3/x - 3;(-4, 4) Maximum A) 7 at x = 4 B) 1/7 at x = -4 C) No absolut

Question

F (x) = x + 3/x - 3;(-4, 4) Maximum A) 7 at x = 4 B) 1/7 at x = -4 C) No absolute maximum D) -1 at x = 0 f (x) = (x^2 + 4)^2/3;[-2, 2] Minimum A) 4 at x = 2 B) No absolute minimum C) 2.5198 at x = 0 D) 2.924 at x = 1 f (x) = (x + 1)^2 (x - 2);[-2, 1] Maximum A) -4 at x = -2 B) No absolute maximum C) -2 at x = 0 D) 0 at x = -1 f (x) = 3x^4 + 16x^3 + 24x^2 + 32;[-3, 1] Maximum A) 59 at x = -3 B) 75 at x = 1 C) 48 at x = -2 D) 32 at x = 0 f (x) = x^4/3 - x^2/3;[0, 2] Minimum A) 0.9324 at x = 2 B) 0 at x = 1 C) No absolute minimum D) -1/4 at x = Squareroot 2/4

Explanation / Answer

maximum is 7 at x=4

f(x) = (x+3)/(x-3) at [-4,4]

1) if x =4, then f(x) = 4+3/4-3 =7

2) if x =-4, then f(x) = -4+3/-4-3 = 1/7

3) if x=0, then f(x) = 3/-3 = -1

above you can see the maximum value we will get is 7 .

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