. . Home work 15:Applications/E/XwA Practice Another Version ×wA3a30153319a334e3
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. . Home work 15:Applications/E/XwA Practice Another Version ×wA3a30153319a334e363d82f7XV-23-0.10(101)+0.0012(101/ × d wwww.webassign.net/web/Student/Assignment-Responses/last?dep#16336642#04 Apps 2/3 points | Previous Answers SCalcET8 3.7.506.XP My Notes The cost function for production of a commodity is E(x) = 369 + 29x-0.06x2 + 0.0007x3 (a) Find C(100) 38 Interpret C(100) This is the number of items that must be produced before the costs reach 100 This is the rate at which costs are increasing with respect to the production level when x-100 O This is the amount of time, in minutes, it takes to produce 100 items This is the rate at which the production level is decreasing with respect to the cost when x = 100 This is the cost of making 100 items. (b) Find the actual cost of producing the 101st item. (Round your answer to the nearest cent.) 38.3 Enhanced Feedback Please try again. For part (a), find the derivative of C and evaluate it for the given value. For part (b), the cost of the nth item is C(n)- C(n - 1). Need Help?Read It Talk to a Tutor Submit Answer Save Progress Practice Another Version 2/2 points | Previous Answers SCalcET8 3.7.508.XP My NotesExplanation / Answer
C(x)= 369 + 29x - 0.06x2 + 0.0007x3
For part (b)
Cost of nth item = C(n) - C(n-1)
Cost of 101st item = C(101) - C(100) = 29(101) - 0.06(101)2 + 0.0007(101)3 - 29(100) + 0.06(100)2 - 0.0007(100)3
= 38.1507 = 38.15 cent (nearest cent i.e round to 2 decimal place)
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