Which is closest to the volume (measured in cubic units) of the solid whose base

Question

1. Which is closest to the volume (measured in cubic units) of the solid whose base is bounded below by the circle with its center as (0,0) and whose radius is 2? The indicated cross sections taken perpendicular to the x-axis are isosceles right triangles.

1. Which is closest to the volume (measured in cubic units) of the solid whose base is bounded below by the circle with its center as (0,0) and whose radius is 2? The indicated cross sections taken perpendicular to the x-axis are isosceles right triangles.

Explanation / Answer

I'm sorry, the the area of the triangle is 1/2b*h, but both the base and the height is a. Therefore the area would be 1/2a2=4-x2. Everything would remain the same except for there would be no 2.

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