Given f(x) = 3x + sinx -e^(x) Write a MATLAB user-defined function named Falsepo

Question

Given f(x) = 3x + sinx -e^(x)

Write a MATLAB user-defined function named

Falseposition to solve the equation f(x)=0 with Regula falsi method. Use x(0)= 0 and x(1) =1

as the starting values and a tolerance= 10^(-7)

.

The program should include the following features:

a) The two initial value, the tolerance and the function f are the input of the

Falseposition function and its output is the approximate solution

b) Display the iteration number and the approximate solution iteration by iteration.

c) Use the approximate relative error as the stop criterion and when it

Explanation / Answer

function [ solution ] = Falseposition(input1,input2,tolerance)
%UNTITLED6 Summary of this function goes here
%   Detailed explanation goes here
x=linspace(0,1,10);

a=input1;
b=input2;
f = @(y)3*y + sin(y) - exp(-y); %function which root is needed

c=0;
s=0;   %iteration number variable
for cnt=2:length(x);
    s    %iteration number
    c=b-(f(b)*(b-a))/(f(b)-f(a)) %approximate solution
    if f(a)*f(c)<0
        b=c;
    else a=c;
    if abs(f(c)<tolerance)
        cnt=length(x);f(c)
    else cnt=2
    end
    end
    s=s+1;
end
solution=c
s




end

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