A right triangle whose base is 30 units is divided into two parts by a line draw

Question

A right triangle whose base is 30 units is divided into two parts by a line drawn parallel to the base. It is given that the resulting right trapezoid has an area larger by 7,0 (which is sexagesimal) = 420 than the upper triangle, and that the difference between the height y of the upper triangle and the height z of the trapezoid is 20. if x is the length fo the upper base of the trapezoid, these statement lead to the relations 1/2z (x+30) = 1/2xy + 420, y - z = 20. The problem calls for finding the values of the unknown quantities x, y, and z.

[Hint: By properties of similar triangles, y/(y+z) = x/30.]

Explanation / Answer

IN TRIANGLE ABC

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