Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n,

ID: 2903114 • Letter: P

Question

Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n, n) + C(2n, n-1). The proof must show proof of equality by left hand side and right hand side. Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n, n) + C(2n, n-1). The proof must show proof of equality by left hand side and right hand side. Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n, n) + C(2n, n-1). The proof must show proof of equality by left hand side and right hand side. Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n, n) + C(2n, n-1). The proof must show proof of equality by left hand side and right hand side.

Explanation / Answer

we have,C(n,r) = C(n-1,r-1) + C(n-1,r)

given RHS

C(2n, n+1) + 2*C(2n, n) + C(2n, n-1)

C(2n, n+1) + C(2n, n) + C(2n, n) + C(2n, n-1)

C(2n+1, n+1) + C(2n+1, n)

C(2n+2, n+1)

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Prove the following combinatorial relation: C(2n+2, n+1) = C(2n, n+1) + 2*C(2n,

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