In a survey of men in a certain country (ages 20-29), the mean height was 64.1 i

Question

In a survey of men in a certain country (ages 20-29), the mean height was 64.1 inches with a standard deviation of 29 inches. (a) What height represents the 99th percentile? (b) What height represents the first quartile? Click to view page 1 of the Standard Normal Table. Click to view page 2 of the Standard Normal Table (a) The height that represents the 99th percentile is ? inches. (Round to two decimal places as needed.) (b) The height that represents the first quartile is ? inches. Round to two decimal places as needed.)

Explanation / Answer

Here' the answer to the question with full concept. Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer

We use the Z tables to find the percentile' Z value.

a. 99th percentile is : Mean + Z*Stdev = 64.1 + 2.326*2.9 = 70.85 inches

For 1st quartile , we have Z = 64.1 -.675*2.9 = 62.14 inches

a. 99th percentile is : Mean + Z*Stdev = 64.1 + 2.326*2.9 = 70.85

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.