Lab 7 Student Worksheet-STA 296 - Summer 2018 (Compatibility Mode] Mailings Revi
ID: 2908568 • Letter: L
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Lab 7 Student Worksheet-STA 296 - Summer 2018 (Compatibility Mode] Mailings Review View Table Design Layout docx, or pdf Workbook Problems 1. Beyond the Numbers 3.30-Exhibit 1 Instead of conducting a hypothesis test for a single proportion, test Ho = P2 against Ha: P.> P2 with significance level ?-01, where "1" denotes morin and "2" denotes the placebo. Consequently, P-102/950 107 and p2 67/920-073 Include unsimplified and simplified versions of the standard error in your assignment, along with the test statistic, the p-value, and the correct decision regarding Ho. Use StatKey to find the p-value, and copy a screenshot into your assignment. If you crop your screenshot, make sure it includes a graph of the appropriate theoretical distribution, along with the parameters visible toward the right of the screen. Additional Problems 2. The "fog index is used to measure the reading difficulty of a written text. The fog index is computed as the sum of the average number of words per sentence plus the percentage of words with three or more syllables. A random sample of 25 paget of the Wall Street Journal had a mean fog index of 48.72 with standard deviation 12.46. A random sample of 28 pages of Sports Illustrated had a mean fog index of 37.85 with standard deviation 15.39. Assume the fog index of a page is normally distributed for both magazines. Do the data indicate that the mean fog indices of the Wall Street Journal and Sports Illustrated are different? Use a 5% level of significance. (a) Are the data paired or independent? (b) Based on the answer to part a, compute the standard errer tc) Using the answer to part b, compute the test statisticExplanation / Answer
pcap = 102/950 = 0.1074
SE = sqrt(0.0728*(1-0.0728)/950) = 0.0084
Test statistic,
z = (0.1074 - 0.0728)/0.0084
z = 4.1047
p-value = 0.00002
As p-value is less than the significance level of 0.01, we reject the null hypothesis.
Hence there are significant evidence to conclude that the true proportion of all Vytorin users who develp cancer while taking the drug is greater than 0.0728.
Chose Ha
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