1 Growth and Tradeshare 2 TradeShare Growth 0.140501976 1.9159931 0.156622976 0.
ID: 2908953 • Letter: 1
Question
1 Growth and Tradeshare 2 TradeShare Growth 0.140501976 1.9159931 0.156622976 0.624283 0.157703221 4.312184 0.160405085 2.930598 0.160815045 1.720469 0.22145839 0.711739 0.299405932 2.890181 0.31307286 2.233012 0.324612707 0.065032 0.324745566 -0.65377 0.3294792471 1.984944i 0.3300216792.93979 0.337879002 3.231227 10 01 13 14. 15 16 17 0.339706242 2.438649 0.3523176312.80924 0.358856708 1.032228 0.393250912 1.979744 0.41760394 2.703513 0.425837249-2.74949 0.43557933 0.358499 0.442142904 2.455842 0.444374621 2.389798 0.450546652 1.968693 0.455769301 1.127696i 0.46834?566| 1.159265 0.473254889 2.807552 0.484600782-0.88309 0.488949597 7.163584 0.509590268 0.92955 0.517664552 0.59996 0.5277733211-0.59756 0.534684658 1.45282 0.543337107 4.877881 0.544243515 1.897523 0.550812602-0.43176 19 21 23 24 25 26 27 28 29 31 32 7 35 36 37 0.552722335 1.123182 0.560642541 2.397789 0.56074965 2.18713 0.567130983 1.431107 0.575274825 2.893976 0.582814276 0.84432 39 AT 42 43 14 45 0.603035331 2.38350 2i 0.605031252 1.623296 0.613616884 3.653324 0.626079738 0.469753 0.639484167 3.014984 0.646913528 2.811561 0.651203632 0.393591 0.681555152 3.184772 0.69943291 0.3391 0.704819918 2.500896 0.729232311-0.95719 0.742971599 2.709292 0.745497823 6.632725 0.779847086 2.027911 0.798375845 1.127159 0.814710021 1.969113 47 49 52 53 57 59Explanation / Answer
b1 = 1.6797 ,
se(b1) = 0.9876
for df = 62 , and 90 % confidence level ,
t = t.inv.2t(0.1,62)
= 1.669804163
hence
confidence interval =
(1.6797 - 1.669804163* 0.9876 , 1.6797 + 1.669804163* 0.9876)
= (0.0306014086, 3.32879859138)
= (0.031 , 3.329)
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