The following table represents a plan for a project: b. Indicate the critical pa
ID: 2909745 • Letter: T
Question
The following table represents a plan for a project:
b. Indicate the critical path.
c. What is the expected completion time for the project? (Round your answer to 2 decimal places.)
Expected completion time days
d. You can accomplish any one of the following at an additional cost of $2,500 and if you will save $1,700 for each day that the earliest completion time is reduced, which action, if any, would you choose?
1. Reduce job 2 by three days.
2. Reduce job 6 by two days.
3. Reduce job 10 by two days.
e. What is the probability that the project will take more than 29 days to complete? (Round your answer to 2 decimal places.)
Probability
PREDECESSORJOB(S) TIMES (DAYS) JOB NO. a m b 1 – 2 4 6 2 1 3 3 15 3 1 3 4 11 4 1 1 2 9 5 2 2 6 7 6 3 3 7 8 7 4 4 6 8 8 5,6 2 3 4 9 8 1 4 7 10 7 3 4 5 11 9,10 5 6 7
Explanation / Answer
from the given project
b) the critical path from 1--2--5---8----9------11 the duration =23,5 days
the critical path from 1---4----7----10-----11 the duration = 19 days
the critical path from 1----2---5----8 the duration = 13.5 days
the critical path from 1---3-----6-----8-----9----11 the duration = 24.5 days
c) Expected completion time of the project = 28.5 days
d) reduce job 2 by 2 days
e) expected completion time = M =28.5
dtandard deviation in completion time =1.9493
standard normal variate Z= (29 - 28.5) / 1.9493 = 0.2563
probability that the project will take more than 29 days P(D> 29) = P( Z> 0.2565 ) = 0.5+ P(0<Z<0.2565)
= 0.5 + 0.01 =0.51
51% chance that the project duration may be extend 29 days
JOB NO. predecessor job shortest time a Most likely time m longest time b Expected time a+4m+b /6 variance in time ((b-a) /6 )2 1 - 2 4 6 4 0.11 2 1 3 3 15 5 4 3 1 3 4 11 5 1.78 4 1 1 2 9 3 1.78 5 2 2 6 7 5.5 0.69 6 3 3 7 8 6.5 0.69 7 4 4 6 8 6 0.44 8 5,6 2 3 4 3 0.11 9 8 1 4 7 4 1 10 7 3 4 5 4 0.11 11 9,10 5 6 7 6 0.11Related Questions
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