Q. 11-Q.30 carry two marks each. Player P tosses 4 fair coins and player P2 toss
ID: 2909812 • Letter: Q
Question
Q. 11-Q.30 carry two marks each. Player P tosses 4 fair coins and player P2 tosses a fair die independently of P. The probability that number of heads observed is more than the number on the upper face of the die, equals 17 (B) 32 16 96 Q. 12 ) Let ?, and X2 be iid. continuous random variables with the probability density function 0, otherwise rond Using Chebyshey'sinsquality. the lower bound of P (, +-11) 13 het X1.x2.Xy be i.i.d discrete random variables with the probability mass function p1.2. p(k) Let Y x X2 + X3. Then P(Y 2 5) equals 25 27 27 14 Let X and Y be continuous random variables with the joint probability density function f(xy)-(cx(1-x), if 0Explanation / Answer
As we aren't supposed to answer assignment questions, let me take up Q11, the first question. Here' the answer to the question with full concept. Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer
Q11. P1 tosses 4 fair coins
P2 tosses independely a fair die.
P(heads of P1> number of upper face of die)
2 /3 /4 heads can come out.
P(2 heads is got and 1 is got on die)+P(3 heads are got and either 2or1 is got on die)+P(4 heads and either of 3,2or1 is got on die)
= (COMBIN(4,2)*(1/2)^4)*(1/6) + (COMBIN(4,3)*(1/2)^4 )* (2/6) + (COMBIN(4,4)*(1/2)^4)*(3/6))
= .1771 = 17/96
Answer is C.
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